i noticed a decline in enthusiasm for learning, so i decided to tackle this century-long problem!
I noticed a decline in enthusiasm for learning, so I decided to tackle this century-long problem!
1* A smallest standard right triangle ABC of the light day.
- It has one right-angle side: AB = 1/√Φ
- And a pair of right-angle sides are AC with values : AC = 1
- It has a hypotenuse BC with value: BC= √Φ
=> Area of a smallest standard right triangle ABC:
A1 of ∆ = 1/2 × AB × AC = 1/2 × 1 × 1/√Φ = 1/(2√Φ)
2* A smallest standard right triangle ABC of the dark night.
- It has one right-angle side: AB = 1
- And a pair of right-angle sides are AC with values: AC = √Φ
- It has a hypotenuse BC with value: BC= Φ
=> Area of a smallest standard right triangle ABC:
A2 of ∆ = 1/2 × AB × AC = 1/2 × 1 × √Φ = (√Φ)/2
3* A smallest standard right triangle ABC of the Pythagoras.
- It has one right-angle side: AB = 1
- And a pair of right-angle sides are AC with values : AC = 1
- It has a hypotenuse BC with value: BC= √2
=> Area of a smallest standard right triangle ABC:
A3 of ∆ = 1/2 × AB × AC = 1/2 × 1 × 1 = 1/2
4* A smallest standard right triangle ABC of the Hypotenuse side of 1.
- It has one right-angle side: AB = √3/2
- And a pair of right-angle sides are AC with values : AC = 1/2
- It has a hypotenuse BC with value: BC= 1
=> Area of a smallest standard right triangle ABC:
A3 of ∆ = 1/2 × AB × AC = 1/2 × √3/2 × 1/2 = √3/8
5* A smallest standard circle (D = 1) with (Circle Unit of π):
- The area of the circle: A = π/4
We have all ratio:
=> The area of a smallest standard circle is always larger than A/A1 = (π√Φ)/2 = 2 times the area of a smallest standard right triangle of the light. This Ratio is get perfect index of The Light Golden Ratio.
=> The area of a smallest standard circle is always larger than A/A2 = (π/(2 √Φ)= 1,2349 times the area of a smallest standard right triangle of dark night. This Ratio is get perfect index of The Dark Night Golden Ratio.
=> The area of a smallest standard circle is always larger than A/A3 = π/2 = 1,5708 times the area of a smallest standard right triangle of Pythagoras. This Ratio is get perfect index of The Pythagoras Golden Ratio.
=> The area of a smallest standard circle is always larger than A/A4 = 2π/√3 = 3,6276 times the area of a smallest standard right triangle of Hypotenuse side of 1. This Ratio is get perfect index of The Hypotenuse side of 1 Golden Ratio.
Note:
This ratio shows the level of loyalty
between the golden boy and the golden girl.
The most consistent is
A/A4 = 3,6276, the golden girl still inside the golden boy,
then A/A1 = 2, the golden girl outside the golden boy.
then A/A3 = 1,5708, the golden girl outside the golden boy.
and finally A/A2 = 1,2349: the golden girl outside the golden boy.