tich phan 18 lop cua ham f(a,b,c...etc) cua da thuc 18 bien.
- Tich phan 9 lop cua ham F(a1,b1,c1...etc) cua da thuc 9 bien voi the tich khong doi cua Cay Thu Muc tren bau troi dem Hoan Vu luon luon bang - 1.
Y = V × ∬∬∬∬∫ F(a1,b1,c1...etc)d(a1,b1,c1...etc) = -1.
Luu y:
Voi 9 chieu khong gian va thoi gian nhung ket qua la su co mat cua vi Than Sao Moc o ben Phuc Am nen bang -1.
V: la the tich khong doi cua Cay Thu Muc. Duoc tinh tu Sao Moc den he Mat Troi.
- Tich phan 6 lop cua ham F(a2,b2,c2...etc) cua da thuc 6 bien voi the tich khong doi cua Cay Dai Thu luon luon bang +1.
Y = V × ∬∬∬ F(a2,b2,c2...etc)d(a2,b2,c2...etc) = +1.
Luu y:
Voi 6 chieu khong gian va thoi gian nhung ket qua la su co mat cua nhung vi Chan Su Dac Dao nen bang +1.
V: la the tich khong doi cua Cay Dai Thu. Duoc tinh tu Trai dat den he Mat Troi.
- Tich phan 18 lop cua ham F(a,b,c...etc) cua da thuc 18 bien voi the tich khong doi cua Cay Dai Thu va Cay Thu Muc tren bau troi dem Hoan Vu luon luon bang 0.
Y = V1×V2 ∬∬∬∬∬∬∬∬∬ F(a,b,c...etc)d(a,b,c...etc) = 0.
Luu y:
Voi 18 chieu khong gian va thoi gian, la su ket hop giua Cay Dai Thu va Cay Thu Muc tren Bau Troi Dem Hoan Vu triet tieu lan nhau nen luon luon cho ket qua la bang 0.
V1: la the tich khong doi cua Cay Thu Muc. Duoc tinh tu Sao Moc den he Mat Troi.
V2: la the tich khong doi cua Cay Dai Thu. Duoc tinh tu bang tong cua the tich tu trai dat den mat troi va tu trai dat den sao moc.
Co hai cach tinh co the tach rieng biet hoac co the ket hop lai voi nhau nhung deu cho ket qua cua Tich phan 18 lop luon luon bang 0.
Translate:
- The 9-fold integral of the function F(a1,b1,c1...etc) of the 9-variable polynomial with the constant volume of the Directory Tree in the Universal Night Sky is always equal to -1.
Y = V × ∬∬∬∬∫ F(a1,b1,c1...etc)d(a1,b1,c1...etc) = -1.
Note:
With 9 dimensions of space and time, but the result is the presence of the God Jupiter in the Gospel, so it equals -1.
V: is the constant volume of the Directory Tree. Calculated from Jupiter to the Solar System.
- The 6-fold integral of the function F(a2,b2,c2...etc) of the 6-variable polynomial with the constant volume of the Great Tree is always equal to +1.
Y = V × ∬∬∬ F(a2,b2,c2...etc)d(a2,b2,c2...etc) = +1.
Note:
With 6 dimensions of space and time, but the result is the presence of enlightened masters, so it equals +1.
V: is the constant volume of the Great Tree. Calculated from Earth to the Solar System.
- The 18-layer integral of the function F(a,b,c...etc) of the 18-variable polynomial with the constant volume of the Great Tree and the Directory Tree in the Universal Night Sky is always equal to 0.
Y = V1×V2 ∬∬∬∬∬∬∬∬∬ F(a,b,c...etc)d(a,b,c...etc) = 0.
Note:
With 18 dimensions of space and time, the combination of the Great Tree and the Directory Tree in the Universal Night Sky cancels each other out, so the result is always 0.
V1: is the constant volume of the Directory Tree. Calculated from Jupiter to the Solar System.
V2: is the constant volume of the Great Tree. Calculated by the sum of the volume from Earth to the Sun and from Earth to Jupiter.
There are two methods of calculation that can be performed separately or combined, but both result in the 18-layer integral always equaling 0.