=> r1 × r2 = √ (0.6 × q × m).

If, throughout space and time, the electric field strength and the gravitational force are inversely proportional to each other, it means that a very large electric field will completely negate the gravitational force. In this case, we are considering two fundamental particles: the photons and the atoms, which are the most abundant particles in space.

The gravitational force is defined as the idea that everything attracts everything, that everything is constantly being created and expanded, partly due to the strength of the gravitational force.

Thus we have:

Electric field strength at a point under investigation × Gravitational field strength at a point under investigation = 1.

1. Electric field strength generated by atoms:

Ee = k × Q / r1^2 (V/m).

Where:

Ee: Electric field strength at a point under investigation (V/m).

k: is the electric field constant, k = 9 × 10^9 (N×m^2 /C^2).

Q: is the source charge (C).

r1: is the distance from the charge (Atom) to the point under investigation (m).

2. Gravitational field strength generated by photons:

Eh = G × M/ r2^2 (Kg ×m/s^2).

In which:

Eh: The gravitational field intensity at a point under investigation (N/Kg) or (Kg × m/s^2).

G: is the gravitational constant, G = 6.674 × 10^-11 (N × m^2 / Kg^2)
M: the mass of the object (photon) creating the gravitational field (Kg).

r2: the distance from the center of the object (photon) to the point under investigation (m).

We have:

=> Ee × Eh = 1.

=> ( k × Q / r1^2) × ( G × M/ r2^2 ) = 1.

=> r1^2 × r2^2 = k × Q × G × M.

=> r1 × r2 = √ (k × Q × G × M).

=> r1 × r2 = √ (0.6 × Q × M).

* In all calculations, inverse proportionality is used to create constraints, and it is this constraint that allows for existence. In this case, we constrain the safe distance between r1 and r2 to the same point of study (r1 + r2 = r), just as a place with an excessively strong electric field will affect the attractive field at that location.

=> r1 × r2 = √ (0.6 × Q × M).

Example: M is the mass of the object. The object is like a photon carrying an gravitational field with mass M = 62 kg, located at a distance r1 from the observation point, and the density of the charge (Atom) created is Q = 30 micrometers = 2.89 C, also located at a distance r2 from the observation point.

=> r1 × r2 = √ (0.6 × Q × M) = √ (0.6 × 2.89 × 62) = 107.51

=> r1 × r2 = 107.51 (m)

Choose r1 = 1 (m), then r2 must be 107.51 (m) from the observation point.

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