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kb = 1.380649 × 10⁻²³ (j/k) = kg × m³/s² × s²/m² × 1/m × 1/kg × k.

Tac gia: Mr.Smile
Kb = 1.380649 × 10⁻²³ (J/K) = Kg × m³/s² × s²/m² × 1/m × 1/Kg × K.

=> This is Formula for quantifying Boltzmann's constant.

* The temperature of the Warm Hole at the temporary Singularity—the intersection point between the White Hole and the Black Hole—is:

Tw = Kb × 1/(c² × D(c) × M), (K).

Note:

Tw: Temperature of the Warm Hole (K).

M: Mass of the object containing the Warm Hole (kg).

D(c): Diameter of the event horizon containing the temporary singularity which is source of the wavelength (m).

c: Speed ​​of light, c = 3 × 10⁸ (m/s).

Kb: Boltzmann constant, Kb = 1.380649 × 10⁻²³ (J/K).

* If giving the temperature of the our reality like as the Warm Hole of 37°C and the wavelength λ is generated from Warm Hole, the diameter of the event horizon containing the temporary singularity is:

(37 + 273) = 1.380649 × 10⁻²³ × 1/((3 × 10⁸)² × D(c) × M) (K).

=> D(c) × M = 5 × 10⁻⁴³

We have: M = λ / 1.79 × 10⁻⁸

=> D(c) × λ / (1.79 × 10⁻⁸) = 5 × 10⁻⁴³

=> D(c) × λ = 9 × 10⁻⁵¹

* The meaning of the cosmological constant (denoted by Λ – Lambda) is: Λ = D(c) × λ = 9 × 10⁻⁵¹ (m⁻²).

Any (Warm hole) event horizon diameter acts as a source emitting a wavelength—whether short or long—that propagates through space at the speed of light, 3 × 10⁸ m/s.

Does this mean that humans and all sentient beings are essentially stars on a specific wavelength, emanating from a certain event horizon (wormhole)?

For example:

=> If diameter of the event horizon at center of Galaxy has a diameter D(c) of 9 × 10⁻⁹¹ m, it will emit a long wavelength to space of the whole universe is λ = 10⁴⁰ m.

=> If diameter of the event horizon at center of Sun has a diameter D(c) of 9 × 10⁻⁷⁷ m, it will emit a long wavelength to space of the whole universe is λ = 10²⁶ m.

=> If diameter of the event horizon at center of people with 48 Kg has a diameter D(c) of 10⁻² m = 1cm, it will emit a short wavelength to space of the whole universe is λ = 9 × 10⁻⁴⁹ m.
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