the particle density is: d = total mass of the standard reality / (π × d(c)² × λ)
* The deepest of Warm hole is where of Black hole and White hole meet together that's the meaning of the cosmological constant (denoted by Λ – Lambda) is:
Λ = D(c) × λ = 9 × 10⁻⁵¹ (m⁻²).
D(c): is diameter of the event horizon inside the deepest of Warm hole (m).
λ: is the wavelength emitted relative to the event horizon diameter of the warm hole (m).
* We have:
Area of the event horizon = π × D(c)² (m²).
The particle density is:
D = total mass of the standard reality / (π × D(c)² × λ)
<=> D = total mass of the standard reality / (π × D(c) × Λ)
<=> D = 1.1 × 10⁻¹⁷ / (π × D(c) × 9 × 10⁻⁵¹) (kg/m³)
For example:
1.* Assuming the diameter of the galaxy's event horizon is D(c) = 10⁻⁹¹ (m), then the particle density of the "Warm Hole"—calculated from the deepest singularity at the center of the event horizon between the Black Hole and the White Hole—is:
D = 1.1 × 10⁻¹⁷ / (π × 10⁻⁹¹ × 9 × 10⁻⁵¹) (kg/m³)
=> D = 3.89 × 10¹²³ (kg/m³)
2.* Assuming the diameter of the People's event horizon is D(c) = 10⁻² (m) = 1cm, then the particle density of the "Warm Hole"—calculated from the deepest singularity at the center of the event horizon between the Black Hole and the White Hole—is:
D = 1.1 × 10⁻¹⁷ / (π × 10⁻² × 9 × 10⁻⁵¹) (kg/m³)
=> D = 3.89 × 10³⁴ (kg/m³)
3.* Assuming the diameter of the the most optimal solution's e vent horizon when D(c) = λ = 3 × 10⁻²⁵·⁵ (m), then the particle density of the "Warm Hole"—calculated from the deepest singularity at the center of the event horizon between the Black Hole and the White Hole—is:
D = 1.1 × 10⁻¹⁷ / (π × 3 × 10⁻²⁵·⁵ × 9 × 10⁻⁵¹) (kg/m³)
=> D = 4.1 × 10⁵⁷ (kg/m³); this is equivalent to the particle density of external reality with λ = 1.988 × 10⁻²⁵ (m) , which is:
D = 1.1 × 10⁻¹⁷ / (1.988 × 10⁻²⁵) = 1.4 × 10⁵⁷ (kg/m³).